Anyone here good with Numbers?

I need someone here to do me a big favour.

How many possible four digit codes could I get from 10 different letters?

For example, if I have A,B,C,D,E,F,G,H,I and J, how manydifferent combinationscould I get like AAAA and AFGI etc

thanks!

10000000000

10,000Oleg_Huzwog

Can't be, a 4 digit lock has 10,000 possibilities.

One hundred and seventy three.. :|

.. Million..

...

Methinks..

[QUOTE="Oleg_Huzwog"]10,000Nemme

Can't be, a 4 digit lock has 10,000 possibilities.

[QUOTE="Oleg_Huzwog"]10,000Nemme

Can't be, a 4 digit lock has 10,000 possibilities.

:| That's what this is... 4 digits in a base-10 system. 10*10*10*10 = 10,000.

[QUOTE="Nemme"]

[QUOTE="Oleg_Huzwog"]10,000sca321

Can't be, a 4 digit lock has 10,000 possibilities.

Yes but 10 different combinations of each. The first digit doesn't have to be an 'A' just as the second digit doesn't have to be 'B'.

Look at it this way, a 4 digit lock with numbers 0-9.

It has 000, 0001 , 0002 --> 9999. That's 10,000 different combinations.

[QUOTE="Nemme"]

[QUOTE="Oleg_Huzwog"]10,000Oleg_Huzwog

Can't be, a 4 digit lock has 10,000 possibilities.

:| That's what this is... 4 digits in a base-10 system. 10*10*10*10 = 10,000.

He's using 10 digits and 10 letters.

Oops! Sorry misread the post. You are right. THought he said 10 and 10.

4 digits, 10 letters.

Yep it is 10,00 afterall ;)

[QUOTE="Oleg_Huzwog"]

:| That's what this is... 4 digits in a base-10 system. 10*10*10*10 = 10,000.

Nemme

He's using 10 digits and 10 letters.

No he isn't.

How many possible four digit codes could I get from 10 different letters?

ScottHFC

my best guess is... 3628800

10*9*8*7*6*5*4*3*2*1 :??

otherwise now I really have no idea...

my best guess is... 3628800

10*9*8*7*6*5*4*3*2*1 :??

otherwise now I really have no idea...

bulletsword

It's 10,000. 10 options for first digit, 10 options for second digit, 10 options for third digit, and 10 options for fourth digit.

:lol: wow i must sound like an idiot. don't have math this tri of school so i'm kind of dumbed out bulletsword

Naw, you were just confusing it with a similar problem: how many combinations can be made without reusing any, in which case the answer is 10*9*8*7 = 5,040.

There are two answers. The first one is 10*10*10*10=10,000. This is the correct answer if and only if every letter in said set can be reused throughout the outcome. The second asnwer is 10*9*8*7=5040. This is correct if and only if each letter in said set can only be used once.

That will be $0.73 for my help.