MATH help please!!

ok, first of all, im not asking for the answer, i'd like to actually know how to do it, so please explain how you got the answer.

here is the problem:  Darren is selling tickets for teh school play. Regular tickets are $4.00 each and student tickets are $3.00 each. darren sells a total of 190 tickets and collects $650. How many of each kind of ticket did he sell?

and if you could, please do this ASAP. im really, really tired. 

x + y = 190

4x + 3y = 650

x = Regular Tickets

y = Student Tickets

That's all I'm saying...zakkro

eh seems these guys are faster then me at this stuff late at night...meh I think I've taken too much Calculus. :lol:Reddragon9288

[QUOTE="Reddragon9288"]eh seems these guys are faster then me at this stuff late at night...meh I think I've taken too much Calculus. :lol:Brewmaster6

grr. so im following what you guys are saying and what my book is saying, but its not seeming to work

i take x+y=190 and make it y=190-x, right?

then how do i get the other equation to work? 

grr. so im following what you guys are saying and what my book is saying, but its not seeming to work

 

i take x+y=190 and make it y=190-x, right?

 

then how do i get the other equation to work? 

KingJustinII

the two equations:

4x + 3(190 - x) = 650

4(190 - y) + 3y = 650

just making sure im doing this right now:

i have 4x+3(190-x)=650, then i distribute the 3 and get 4x+270-3x=650. and then i combine the 4 and 3 x to get x+270=650, then i subtract 270 from 650 to get 380 and then plug in the x acordingly.

sorry if i screwed up, math, if you cant tell, is not my strong point. 

so he sold 80 four dollar tickets and 110 three dollar tickets? i think thats right, thanks guys :)KingJustinII

so he sold 80 four dollar tickets and 110 three dollar tickets? i think thats right, thanks guys :)KingJustinll