Your favorite equation

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Chessy_Nachos

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#1 Chessy_Nachos
Member since 2006 • 1563 Posts

it can be anything math, physics, a joke like the one where girls = evil and the proof for it.

my is e^ix= cos x + i sin x 

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DEATH_GODX

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#2 DEATH_GODX
Member since 2004 • 1473 Posts
F=ma
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foxhound_fox

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#3 foxhound_fox
Member since 2005 • 98532 Posts
The square root of 2 divided by 2 equaling the square root sign.
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Canuck3000

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#4 Canuck3000
Member since 2004 • 40562 Posts
I hate math...
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Robograndma

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#5 Robograndma
Member since 2006 • 2916 Posts
Cincinnati bengals+alcohol=arrest
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a55assin

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#6 a55assin
Member since 2005 • 7603 Posts

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it  

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XxXFaTTxMaTTXxX

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#7 XxXFaTTxMaTTXxX
Member since 2005 • 1483 Posts
(-b +/- (b^2-(4)(a)(c))^(1/2))/2a
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Tanner911

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#8 Tanner911
Member since 2006 • 815 Posts
left divided by right equals... HOLY ****!!! Up!!!
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Nisstyre_56

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#9 Nisstyre_56
Member since 2006 • 2849 Posts
Ek=1/2 mv^2
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Chessy_Nachos

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#10 Chessy_Nachos
Member since 2006 • 1563 Posts

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it

a55assin
Cool
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Robograndma

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#11 Robograndma
Member since 2006 • 2916 Posts

I could prove that 0=1 ^ 0=2

It would take a while do do it on a forum though...I might scan it

a55assin
correct me if i am wrong but dosen't X^0 equal 1?
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Video_Game_King

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#12 Video_Game_King
Member since 2003 • 27545 Posts
Jock+nerd=ass kicking and head aches. Guess who's the jock? ME!!
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Omni-Slash

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#13 Omni-Slash
Member since 2003 • 54450 Posts
.....
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FragStains

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#14 FragStains
Member since 2003 • 20668 Posts
I'd like to say quadratic, but I rarely use that one. So in that case:
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a55assin

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#15 a55assin
Member since 2005 • 7603 Posts
[QUOTE="a55assin"]

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it

Robograndma

correct me if i am wrong but dosen't X^0 equal 1?

 

Totally different...I could prove it with an equation...try proving that 0=2...c'mon. 

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XxXFaTTxMaTTXxX

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#16 XxXFaTTxMaTTXxX
Member since 2005 • 1483 Posts
:lol:
.....Omni-Slash
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jerami

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#17 jerami
Member since 2003 • 1676 Posts

it can be anything math, physics, a joke like the one where girls = evil and the proof for it.

my is e^ix= cos x + i sin x 

Chessy_Nachos
Why yes, that is a very good one. My favorite is probably for momentum... p=mv. Mostly because P in no way is related to the word momentum haha.. But my very favorite equations are the ones that I learned towards the end of Physics last year where there were so many greek letters that it looked like absolute jibberish.... those just made me chuckle
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Chessy_Nachos

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#18 Chessy_Nachos
Member since 2006 • 1563 Posts
[QUOTE="a55assin"]

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it

Robograndma
correct me if i am wrong but dosen't X^0 equal 1?

0^0= undefined if you take the limit coming from both side for example 0 to any power is 0 untill you get the power of zero then you have no idea what it is as it implies dividing by zero. but any number thats not zero to the power of zero is one and the same thing happens when you reach zero it is undefined.
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Flaming_Ape

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#19 Flaming_Ape
Member since 2007 • 3246 Posts
Hot girls=big hawt boobs. :oops:
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194197844077667059316682358889

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#20 194197844077667059316682358889
Member since 2003 • 49173 Posts
Quadratic formula is a fave in the "simple" vein, but Maxwell's field equations blew my mind when I first started studying them:



That was the beginning of field unification theory, as well as the basis for all electromagnetic technology, such as radio, X-rays, WiFi, etc. That's a lot out of 4 little equations.
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Flaming_Ape

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#21 Flaming_Ape
Member since 2007 • 3246 Posts
I hate math...Canuck3000
Then Canuck3000=math hater.
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a55assin

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#22 a55assin
Member since 2005 • 7603 Posts

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. a(a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

 

oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol

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Chessy_Nachos

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#23 Chessy_Nachos
Member since 2006 • 1563 Posts

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it

a55assin
I have no idea how you can make 0=2. Does it have anything to do with (i) the imaginary unit or complex numbers?
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quiglythegreat

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#24 quiglythegreat
Member since 2006 • 16886 Posts
Math sucks. It is a highly sterile language describing few things because it really eliminates ambiguities. That's the worst part about it.
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tomxizor

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#25 tomxizor
Member since 2004 • 11767 Posts
Porn+KY=Good fun on a Saturday Night.
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Chessy_Nachos

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#26 Chessy_Nachos
Member since 2006 • 1563 Posts

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

 

oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol

a55assin
nice:P
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194197844077667059316682358889

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#27 194197844077667059316682358889
Member since 2003 • 49173 Posts
 

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

a55assin
Step 7 to 8, an a was divided out on the left and not on the right.
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a55assin

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#28 a55assin
Member since 2005 • 7603 Posts
[QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

 

oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol

Chessy_Nachos

nice:P

 

If you can understand it...it is. 

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_Goliath_

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#29 _Goliath_
Member since 2004 • 12845 Posts
.....Omni-Slash
the original was women = evil, this one is just a cheap copy...shame on you omni :|
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194197844077667059316682358889

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#30 194197844077667059316682358889
Member since 2003 • 49173 Posts
[QUOTE="a55assin"]

I could prove that 0=1 ^ 0=2

 

It would take a while do do it on a forum though...I might scan it

Chessy_Nachos
I have no idea how you can make 0=2. Does it have anything to do with (i) the imaginary unit or complex numbers?

Such tricks are usually based around taking a square root or factoring in a way that ignores the fact that all numbers have two square roots.
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a55assin

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#31 a55assin
Member since 2005 • 7603 Posts
[QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

xaos

Step 7 to 8, an a was divided out on the left and not on the right.

 

Step 7 and 8 consist of the Distributive property.

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Aznsilvrboy

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#32 Aznsilvrboy
Member since 2002 • 11495 Posts
[QUOTE="xaos"][QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

a55assin

Step 7 to 8, an a was divided out on the left and not on the right.

 

Step 7 and 8 consist of the Distributive property.

 He meant that step 8 should be:

 8. a(a - b) = (a - b)(b + 2)

thats how you got to

9. a = b + 2

by dividing both sides by (a-b).

the a was missing on the left side in 8. 

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194197844077667059316682358889

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#33 194197844077667059316682358889
Member since 2003 • 49173 Posts
[QUOTE="xaos"][QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

a55assin

Step 7 to 8, an a was divided out on the left and not on the right.

 

Step 7 and 8 consist of the Distributive property.

Yeah, I saw that it came bacj in step 9; there was just a typo in step 8 where you forgot to show it on the left. Step 8 to 9 is where the proof breaks down of course, since you are factoring out 0 on each side (a - b, where a = b) and that could be used to set any equality in the proof. Admittedly, I had to copy it into notepad and search/replace "b" with "a" to make it obvious to me :)
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a55assin

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#34 a55assin
Member since 2005 • 7603 Posts
[QUOTE="a55assin"][QUOTE="xaos"][QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

Aznsilvrboy

Step 7 to 8, an a was divided out on the left and not on the right.

 

Step 7 and 8 consist of the Distributive property.

He meant that step 8 should be:

8. a(a - b) = (a - b)(b + 2)

thats how you got to

9. a = b + 2

by dividing both sides by (a-b).

the a was missing on the left side in 8.

 

OH crap...I'm sorry, that was stupid of me. 

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a55assin

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#35 a55assin
Member since 2005 • 7603 Posts
[QUOTE="a55assin"][QUOTE="xaos"][QUOTE="a55assin"]

Given that a and b are integers such that a = b, Prove: 0 = 2

 

1. a = b

2. a - b - 2 = a - b - 2

3. a(a - b - 2) = b(a - b - 2)

4. a2 - ab - 2a = ab - b2 - 2b

5. a2 - ab = ab - b2 - 2b + 2a

6. a2 - ab = ab + 2a - b2 - 2b

7. a(a - b) = a(b + 2) - b(b + 2)

8. (a - b) = (a - b)(b + 2)

9. a = b + 2

10. b = b + 2

11. Thereforem 0 = 2

xaos

Step 7 to 8, an a was divided out on the left and not on the right.

 

Step 7 and 8 consist of the Distributive property.

Yeah, I saw that it came bacj in step 9; there was just a typo in step 8 where you forgot to show it on the left. Step 8 to 9 is where the proof breaks down of course, since you are factoring out 0 on each side (a - b, where a = b) and that could be used to set any equality in the proof. Admittedly, I had to copy it into notepad and search/replace "b" with "a" to make it obvious to me :)

 

Congrats...lol 

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The_Ish

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#36 The_Ish
Member since 2006 • 13913 Posts

You people and your mathematics...

Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?

You're all just wasting your time. :P 

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1fast6

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#37 1fast6
Member since 2004 • 729 Posts

sorry omni... step 1 is flawed... woman is time "and" money equates to woman = time+ money...

heres mine...

theorem to test the legality of a hook up =(b4i) 4q ( ru/18 ) QT(pi)
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194197844077667059316682358889

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#38 194197844077667059316682358889
Member since 2003 • 49173 Posts

You people and your mathematics...

Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?

You're all just wasting your time. :P 

The_Ish
I don't need proof, I just need it to work :)
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Chessy_Nachos

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#39 Chessy_Nachos
Member since 2006 • 1563 Posts

You people and your mathematics...

Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?

You're all just wasting your time. :P

The_Ish
No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry:
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194197844077667059316682358889

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#40 194197844077667059316682358889
Member since 2003 • 49173 Posts
[QUOTE="The_Ish"]

You people and your mathematics...

Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?

You're all just wasting your time. :P

Chessy_Nachos
No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry:

Because it is not a theorem in mathematics but rather in mathematical logic. Conventional arithmetic such as we all learned in school is only one of a potentially infinite set of forms of mathematics that can be defined. Arithmetic just happens to correspond nicely with the physical world of our experience, which is why that system is so prevalent. My bf could explain it a lot better, since he loves diddling with mathematical logic and set theory and model theory and all that jazz for fun.
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kevass007

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#41 kevass007
Member since 2006 • 725 Posts
i dont have one:), i keep my favourites seperate from my equations
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haloraider

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#42 haloraider
Member since 2006 • 3110 Posts

funnyexam

And heres one to go:

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#43 Chessy_Nachos
Member since 2006 • 1563 Posts

funnyexam

And heres one to go:

haloraider
lol a^n +b^n
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The_Ish

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#44 The_Ish
Member since 2006 • 13913 Posts
[QUOTE="The_Ish"]

You people and your mathematics...

Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?

You're all just wasting your time. :P

Chessy_Nachos

No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry:

It's actually pretty famous (especially among Comp. Sci. majors):

http://www.mozilla.org/editor/midasdemo/securityprefs.html

The only problem you might find is that you might have to know some Discrete Mathematics beforehand. :?

 

 

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04JETTA

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#45 04JETTA
Member since 2005 • 5769 Posts
high supply=low demand high demand=low supply
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#46 SimpJee
Member since 2002 • 18309 Posts

 .

It's basically the answer to perfection.

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NathanHawkins

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#47 NathanHawkins
Member since 2006 • 4470 Posts
i was a little surprised that einstein's most famous equation wasn't mentioned more at this point.
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darkmaster578

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#48 darkmaster578
Member since 2006 • 2049 Posts

funnyexam

And heres one to go:

haloraider
lol. That's awesome
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jm4847

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#49 jm4847
Member since 2006 • 3535 Posts
Euler's Identity.
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SimpJee

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#50 SimpJee
Member since 2002 • 18309 Posts
.999999999999 = 1 FACT This is seriously a brain ****. STAY AWAY IF YOU VALUE YOUR SANITY!