it can be anything math, physics, a joke like the one where girls = evil and the proof for it.
my is e^ix= cos x + i sin x
This topic is locked from further discussion.
it can be anything math, physics, a joke like the one where girls = evil and the proof for it.
my is e^ix= cos x + i sin x
CoolI could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
a55assin
correct me if i am wrong but dosen't X^0 equal 1?I could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
a55assin
[QUOTE="a55assin"]correct me if i am wrong but dosen't X^0 equal 1?I could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
Robograndma
Totally different...I could prove it with an equation...try proving that 0=2...c'mon.
Why yes, that is a very good one. My favorite is probably for momentum... p=mv. Mostly because P in no way is related to the word momentum haha.. But my very favorite equations are the ones that I learned towards the end of Physics last year where there were so many greek letters that it looked like absolute jibberish.... those just made me chuckleit can be anything math, physics, a joke like the one where girls = evil and the proof for it.
my is e^ix= cos x + i sin x
Chessy_Nachos
[QUOTE="a55assin"]correct me if i am wrong but dosen't X^0 equal 1?0^0= undefined if you take the limit coming from both side for example 0 to any power is 0 untill you get the power of zero then you have no idea what it is as it implies dividing by zero. but any number thats not zero to the power of zero is one and the same thing happens when you reach zero it is undefined.I could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
Robograndma
Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. a(a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol
I have no idea how you can make 0=2. Does it have anything to do with (i) the imaginary unit or complex numbers?I could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
a55assin
nice:PGiven that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol
a55assin
Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
a55assin
[QUOTE="a55assin"]nice:PGiven that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
oh ya..and every of those (a2) and (b2) is actually squared...becuase Im too lazy using the symbol
Chessy_Nachos
If you can understand it...it is.
[QUOTE="a55assin"]I have no idea how you can make 0=2. Does it have anything to do with (i) the imaginary unit or complex numbers? Such tricks are usually based around taking a square root or factoring in a way that ignores the fact that all numbers have two square roots.I could prove that 0=1 ^ 0=2
It would take a while do do it on a forum though...I might scan it
Chessy_Nachos
[QUOTE="a55assin"]Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
xaos
Step 7 and 8 consist of the Distributive property.
[QUOTE="xaos"][QUOTE="a55assin"]Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
a55assin
Step 7 and 8 consist of the Distributive property.
He meant that step 8 should be:
8. a(a - b) = (a - b)(b + 2)
thats how you got to
9. a = b + 2
by dividing both sides by (a-b).
the a was missing on the left side in 8.
[QUOTE="xaos"][QUOTE="a55assin"]Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
a55assin
Step 7 and 8 consist of the Distributive property.
Yeah, I saw that it came bacj in step 9; there was just a typo in step 8 where you forgot to show it on the left. Step 8 to 9 is where the proof breaks down of course, since you are factoring out 0 on each side (a - b, where a = b) and that could be used to set any equality in the proof. Admittedly, I had to copy it into notepad and search/replace "b" with "a" to make it obvious to me :)[QUOTE="a55assin"][QUOTE="xaos"][QUOTE="a55assin"]Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
Aznsilvrboy
Step 7 and 8 consist of the Distributive property.
He meant that step 8 should be:
8. a(a - b) = (a - b)(b + 2)
thats how you got to
9. a = b + 2
by dividing both sides by (a-b).
the a was missing on the left side in 8.
OH crap...I'm sorry, that was stupid of me.
[QUOTE="a55assin"][QUOTE="xaos"][QUOTE="a55assin"]Step 7 to 8, an a was divided out on the left and not on the right.Given that a and b are integers such that a = b, Prove: 0 = 2
1. a = b
2. a - b - 2 = a - b - 2
3. a(a - b - 2) = b(a - b - 2)
4. a2 - ab - 2a = ab - b2 - 2b
5. a2 - ab = ab - b2 - 2b + 2a
6. a2 - ab = ab + 2a - b2 - 2b
7. a(a - b) = a(b + 2) - b(b + 2)
8. (a - b) = (a - b)(b + 2)
9. a = b + 2
10. b = b + 2
11. Thereforem 0 = 2
xaos
Step 7 and 8 consist of the Distributive property.
Yeah, I saw that it came bacj in step 9; there was just a typo in step 8 where you forgot to show it on the left. Step 8 to 9 is where the proof breaks down of course, since you are factoring out 0 on each side (a - b, where a = b) and that could be used to set any equality in the proof. Admittedly, I had to copy it into notepad and search/replace "b" with "a" to make it obvious to me :)
Congrats...lol
I don't need proof, I just need it to work :)You people and your mathematics...
Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?
You're all just wasting your time. :P
The_Ish
No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry:You people and your mathematics...
Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?
You're all just wasting your time. :P
The_Ish
[QUOTE="The_Ish"]No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry: Because it is not a theorem in mathematics but rather in mathematical logic. Conventional arithmetic such as we all learned in school is only one of a potentially infinite set of forms of mathematics that can be defined. Arithmetic just happens to correspond nicely with the physical world of our experience, which is why that system is so prevalent. My bf could explain it a lot better, since he loves diddling with mathematical logic and set theory and model theory and all that jazz for fun.You people and your mathematics...
Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?
You're all just wasting your time. :P
Chessy_Nachos
[QUOTE="The_Ish"]No sadly i have never heard of such a theorem but how is that theorem proven if it states that mathematics is an incomplete proof system? lol:cry:You people and your mathematics...
Don't any of you know of Godel's Incompleteness Theorem that proves that mathematics is an incomplete proof system?
You're all just wasting your time. :P
Chessy_Nachos
It's actually pretty famous (especially among Comp. Sci. majors):
http://www.mozilla.org/editor/midasdemo/securityprefs.html
The only problem you might find is that you might have to know some Discrete Mathematics beforehand. :?
Please Log In to post.
Log in to comment