[QUOTE="xaos"][QUOTE="Mystery_Writer"]how about if A was at 99.9% and B launched at 99.9% relative to A? at what speed B would be travelling to the stationary observer? and at what speed B would be travelling when observed by a person on board object A?Mystery_Writer
Using the simple formula I linked above, the observer at rest relative to A's motion at .999c would see B moving at 99.999949949975% lightspeed. And, obviously, the reference frame of A would see B moving at 99.9% lightspeedman, thanks a lot.. I guess I finally got it when it involves launching object B in the same direction as Object A
i.e. time would slow down so much on Object A that Object B would seem to be moving at 99.9% relative to an observer on Object A.
But how does this time slow down concept work when launching an object in the opposite direction?
i.e. having Object A traveling at 99% and launching B at 99% towards the opposite direction.
According to the formula, B should be travelling at 0% to a stationary observer and would seem to be travelling at 99% away from an observer on board Object A.
However, since time slowed down on Object A, shouldn't the stationary Object B seem to be travelling faster than 99% to an observer on board Object A?
Yes, A and B would each see the other moving away from that at the cumulative speed indicated by the velocity addition formula
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