LOGIC RIDDLE: A jailer has 5 hats...

1) guy1 sees: white / white no idea

2) guy1 sees: white / red no idea

3) guy1 sees: red / white no idea

4) guy1 sees: red / red he knows he's red and is set free

comp_atkins

If any of them sees two reds then he must be white, because there are only two red hats.

[QUOTE="JC346"]What stupid inmates. At least guess what hat you have on, don't just say you don't know. >_>unholymight

But it is stated in the riddle that the prisoners are not allowed to tell each other what colour hats they have on.MetalGear_Ninty

I just figured out where I've gone wrong. The blind man must have a white hat, not a red one.

There are five hats: three white, two red. There are three inmates. That means that any of the following combinations are possible:

All three get white hats. If this is true then the first two inmates would see two white hats and not know whether they have red hats or not, so they get uncertain, leaving the blind man to conclude he must be wearing a white hat.

One gets a white hat, and two get red hats. If this is true then the first two inmates would have to see one white and one red, because if they saw two reds then they would know their hats were white. Since they are uncertain, the blind man knows he must have the white hat.

Two get white hats, and one gets a red hat. If this is true then one of the first two men would see two white hats and one would see one white and one red; their uncertainty of their own hats would lead the blind man to conclude that he has a white hat.

we'll go through each case:

1) guy1 sees: white / white no idea

2) guy1 sees: white / red no idea

3) guy1 sees: red / white no idea

4) guy1 sees: red / red he knows he's red and is set free.. this doesn't happen

guy1 says he doesn't know so only 1,2,3 can be true

5) guy2 sees: white / red no idea

6) guy2 sees: red / white no idea

7) guy2 sees: white / white no idea

8: guy2 sees: red / red he knows he's red and is set free.. this doesn't happen

guy2 knows that guy 1 did not see red / red

if guy 2 saw white / red he would know that he's wearing white because guy 1 did not see red / red .. so 5) and 2) are eliminated

remaining options are 1, 3, 6 and 7 which all have blind guy wearing white.

[QUOTE="unholymight"][QUOTE="Theokhoth"]

I just figured out where I've gone wrong. The blind man must have a white hat, not a red one.

There are five hats: three white, two red. There are three inmates. That means that any of the following combinations are possible:

All three get white hats. If this is true then the first two inmates would see two white hats and not know whether they have red hats or not, so they get uncertain, leaving the blind man to conclude he must be wearing a white hat.

One gets a white hat, and two get red hats. If this is true then the first two inmates would have to see one white and one red, because if they saw two reds then they would know their hats were white. Since they are uncertain, the blind man knows he must have the white hat.

Two get white hats, and one gets a red hat. If this is true then one of the first two men would see two white hats and one would see one white and one red; their uncertainty of their own hats would lead the blind man to conclude that he has a white hat.

Theokhoth

I said, the blind man must be wearing a white hat.

Your logic is also incorrect: if the first man sees red (on the blind man) and white (on the one-eyed man), then the second one would see one white and one red; the uncertainty of the first man would lead the second man to believe that he could be wearing either white or red.

[QUOTE="unholymight"][QUOTE="Theokhoth"]

I just figured out where I've gone wrong. The blind man must have a white hat, not a red one.

There are five hats: three white, two red. There are three inmates. That means that any of the following combinations are possible:

All three get white hats. If this is true then the first two inmates would see two white hats and not know whether they have red hats or not, so they get uncertain, leaving the blind man to conclude he must be wearing a white hat.

One gets a white hat, and two get red hats. If this is true then the first two inmates would have to see one white and one red, because if they saw two reds then they would know their hats were white. Since they are uncertain, the blind man knows he must have the white hat.

Two get white hats, and one gets a red hat. If this is true then one of the first two men would see two white hats and one would see one white and one red; their uncertainty of their own hats would lead the blind man to conclude that he has a white hat.

MetalGear_Ninty

Actually, not both of us, if you read the next posts...

His guide dog barked it out in Morse code.markop2003

This probably. Most logical.

[QUOTE="Theokhoth"]

[QUOTE="unholymight"] I believe you're also missing the part where the blind man can't be red because then the 2nd guy would already know himself to be white.unholymight

I said, the blind man must be wearing a white hat.

Your logic is also incorrect: if the first man sees red (on the blind man) and white (on the one-eyed man), then the second one would see one white and one red; the uncertainty of the first man would lead the second man to believe that he could be wearing either white or red.

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

[QUOTE="unholymight"][QUOTE="Theokhoth"]

I said, the blind man must be wearing a white hat.

Your logic is also incorrect: if the first man sees red (on the blind man) and white (on the one-eyed man), then the second one would see one white and one red; the uncertainty of the first man would lead the second man to believe that he could be wearing either white or red.

Theokhoth

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

[QUOTE="unholymight"][QUOTE="Theokhoth"]

I said, the blind man must be wearing a white hat.

Your logic is also incorrect: if the first man sees red (on the blind man) and white (on the one-eyed man), then the second one would see one white and one red; the uncertainty of the first man would lead the second man to believe that he could be wearing either white or red.

Theokhoth

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

[QUOTE="unholymight"][QUOTE="Theokhoth"]

I said, the blind man must be wearing a white hat.

Your logic is also incorrect: if the first man sees red (on the blind man) and white (on the one-eyed man), then the second one would see one white and one red; the uncertainty of the first man would lead the second man to believe that he could be wearing either white or red.

Theokhoth

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

[QUOTE="Theokhoth"]

[QUOTE="unholymight"] No...the first one will never see red on the blind man because that will cause 2nd guy to know his own color...MetalGear_Ninty

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

[QUOTE="Theokhoth"]

[QUOTE="unholymight"] No...the first one will never see red on the blind man because that will cause 2nd guy to know his own color...MetalGear_Ninty

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

Ah, I get it now:

The first guy would see one white and one red. He knows he could be wearing white or red, and so is uncertain.

The second guy would see both white and red. Based on the uncertainty of the first guy (who is wearing white), he knows one of two things is possible:

All three men are wearing white.

Two is wearing white, and one is wearing red.

The first can't be true, because the blind man is wearing red.

Therefore, he must be wearing white.

Unholymight didn't explain himself. :P

[QUOTE="MetalGear_Ninty"]

[QUOTE="Theokhoth"]

They cannot tell eachother the color of their hats. Your logic requires the assumption that both the blind man and the man with perfect vision have red hats.

Theokhoth

Ah, I get it now:

The first guy would see one white and one red. He knows he could be wearing white or red, and so is uncertain.

The second guy would see both white and red. Based on the uncertainty of the first guy (who is wearing white), he knows one of two things is possible:

All three men are wearing white.

Two is wearing white, and one is wearing red.

The first can't be true, because the blind man is wearing red.

Therefore, he must be wearing white.

Unholymight didn't explain himself. :P

Well....the blind guy's certainly a genius if he can use Theokhoth's logic to determine the colour of his hat.Lansdowne5

I'm not a genius and I can use my logic. :?

[QUOTE="Lansdowne5"]Well....the blind guy's certainly a genius if he can use Theokhoth's logic to determine the colour of his hat.Theokhoth

I'm not a genius and I can use my logic. :?

This site explains it nicely:

Link

This site explains it nicely:

Link

flazzle

Cheater! :x

This site explains it nicely:

Link

flazzle

Well....the blind guy's certainly a genius if he can use Theokhoth's logic to determine the colour of his hat.Lansdowne5

This site explains it nicely:

Link

I give up whats the answer.

The real answer is while the guard is putting the hat on the blind man, the One eyed guy grabs him. The two eyed guy knocks him out grabs his key and steals his uniform. Him and the other two move through the prison quickly, with the other two being escorted. They get through the gate and steal a prison vehicle. The Blind guy goes to spend the rest of his years with family, twoeyes goes to find the man who framed him, and the one eyed guy retires from crime and tries to redeem himself.