So, what happens if an unstoppable force hits an immovable object?

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jeremiah06

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#101 jeremiah06
Member since 2004 • 7217 Posts

Well, technically, there is no such thing as an unstoppable force or immovable object, so this isn't really a phyiscs problem, but simply a matter of word play. However, if they were to collide, the force would just skew around the object.

dackchaar
If the force moves around the object then it isn't unstoppable...
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markop2003

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#102 markop2003
Member since 2005 • 29917 Posts
Deflection or destruction.
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markop2003

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#103 markop2003
Member since 2005 • 29917 Posts
[QUOTE="dackchaar"]

Well, technically, there is no such thing as an unstoppable force or immovable object, so this isn't really a phyiscs problem, but simply a matter of word play. However, if they were to collide, the force would just skew around the object.

jeremiah06
If the force moves around the object then it isn't unstoppable...

Moving around is not stopping and no one said that it was a direct hit, the force could just be deflected parallel to the object.
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BossPerson

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#104 BossPerson
Member since 2011 • 9177 Posts

if only xaos was still here...

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JakeTD21

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#105 JakeTD21
Member since 2007 • 1631 Posts
I can't believe that people are arguing about this. Any number divided by zero= undefined. FACT.
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jediknight52501

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#106 jediknight52501
Member since 2005 • 69715 Posts
he yields. end of discussion.
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Ringx55

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#107 Ringx55
Member since 2008 • 5967 Posts
The unstoable force goes through the immovable object who will still be in perfect condition. Something like that from a old WoW thread in 06.
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Charazani

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#108 Charazani
Member since 2011 • 2919 Posts
[QUOTE="Charazani"][QUOTE="themajormayor"] Coolbeans already explained this to you: "x*0 = 0 => 0/0=x Insert any value for x. x is undefined."stanleycup98
Still do not see why x would not just be all real numbers.

Depending on the type of math you are doing, 0/0 is either undefined or indeterminate. It is undefined in the most basic maths. Why is it undefined? Imagine the equation x * 0 = 0. To find the value of x, you isolate the variable (basic algebra). So you divide both sides by zero...x = 0/0. Now what value of x makes this equation true? Is there a value of x that equals 0/0? The answer is no. Thus, 0/0 is undefined. You are saying that any real number makes that equation true. So say x = 2. Does 2 = 0/0? No. Say x = - 25. Does -25 = 0/0? No. There is no known value for x that makes x = 0/0 true. Now, if you want to see a more advanced explanation, look to Calculus. Imagine a function a/x. Now, take the limit as x approaches 0 of this function from the right. As x gets infinitely closer to 0, x gets infinitely smaller. Basic math shows that as the denominator of a number gets smaller while the numerator remains constant, the number gets larger. So as x gets infinitely small, the function a/x gets infinitely big. Thus, the limit as x approaches 0 from the right is simply infinity (and it is negative infinity as you approach from the left). So, we know that the value of a/x at 0 is infinity. But what is infinity? It is a concept, not a number. You can not define what infinity is in the context of this problem. Thus, a function a/x is undefined. So probably you are asking what happens if a = 0. Using the limits, you will come out with a value of 0/0. This is a special form called an indeterminate form. While slightly different than an undefined value, the idea is still the same. There is no way to define what 0/0 is. Let's say that we have another function x/x. This simplifies to just 1. So, we know the value of this function at 0 is 1. So take the limit as x approaches infinite of x/x. Using straight substitution, you will come out with an answer of 0/0. What does 0/0 equal? In this case, we know that it should equal 1, but you can't say 100% that it does equal 1. Why not? Well, imagine the function 7x/x. Again, this simplifies to just 7, so we know the value at 0 is 7. But take the limit of this using substitution, and you get the form 0/0 again. If 0/0 equaled 1 before, how does it equal 7 now? 1 does not equal 7, therefore, you could say that 0/0 is not a well-defined value. It should be defined as many different things, depending on the situation, and so you can't give it a straight value. That is why it is called indeterminate. We can't determine what a 0/0 equals because it is never defined. So then, moving back to one of your other questions. If a/0 is undefined, how come a*0, a + 0 , or a - 0 are defined? For this, simply think of the idea of 0 being nothing. In it's most simplistic sense, division is the dividing out of equal parts. I have 10 apples, and I want to divide them out to 5 people. Each person gets 2 apples. I have 10 apples, and I want to divide them out to 0 people. This is impossible. I can't divide out 10 apples to nothing. Thus, 10/0 is undefined. Now, this of multiplication as the opposite of this. There are 5 people with 2 apples each. How many apples are there in total? 10. There are 5 people with no apples. How many apples are there in total? 0. Addition and subtraction are even easier. If I have 10 apples, and I add no more apples to my apple collection, I still have 10 apples. And if I have 10 apples, and no one takes any of my apples, I still have 10 apples. Anyway, time to eat some pizza.

Still hold that 0/0 number. So infinitey or negative infinity. Not undefined. In some cases think infinity can be a number. Just that nothing can be done to it to change it. Like of you add something to it , it will not grow because it grows in an infinite manner. Same for subtraction or anything else. Now dividing infinitey by infinity would result in one. Which is the only way to change its state. Because you are basically taking the same thing and asking what part it plays.
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