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nintendo-4life

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#51 nintendo-4life
Member since 2004 • 18281 Posts

And another : 9, 61, 52, 63, 94, ___ , 18 dave123321
31? ...EDIT: DAMMIT i got it wrong >_

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nintendo-4life

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#52 nintendo-4life
Member since 2004 • 18281 Posts

[QUOTE="Theokhoth"]

How did you?

Each number on the right column is a multiple of five higher than the number above it. Each new column adds five more, so I just followed that to its conclusion.

Nope. How did you go about getting this ?


Damn it. :x Same basic logic: the ones place appears to have a pattern: 9, 6, 5, 6, 9. The tens place definitely has a pattern: 1, 2, 3, 4, 5, 6. . . . .again, I just followed it to what I thought was the right step in the pattern.

dave123321

The answer it was looking for was 46. Reverse each number to see the clear pattern.

Edit: looking back your solution does not seem to fit.

I still don't get it... what do you mean by reversing the numbers?

EDIT: oh ok I got it.. but the first 9 seems out of place, other than that it becomes 4*4 (reverse), 5*5 (reverse) etc..

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dave123321

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#53 dave123321
Member since 2003 • 35554 Posts

Another one 1,3,5,20,160,4000,______,2995200000

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Jph625

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#54 Jph625
Member since 2009 • 1046 Posts

logically speaking if they man saw a bunch of other men with brown eyes and they didn't leave would he think that that color isn't brown? and if one man leaves and the guru said one brown eyed man can leave than wouldn't all of them assume that he already left and just stay?

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dave123321

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#55 dave123321
Member since 2003 • 35554 Posts

logically speaking if they man saw a bunch of other men with brown eyes and they didn't leave would he think that that color isn't brown? and if one man leaves and the guru said one brown eyed man can leave than wouldn't all of them assume that he already left and just stay?

Jph625

The idea is that they posses perfect logic. Think of a situation of only one brown eyed person . That person will know automatically that he has brown eyes since he is the only possible brown eyed person the guru sees. With two people , each brown eyed person will see that the other did not leave the first day. The only reason for this is that there is another brown eyed person (themselves).So they leave that day(2nd day) . For 3 people this works out the same , each person sees two other people with brown eyes. The fact that they did not leave on the 2nd day proves that there is another person with brown eyes(themselves) . They leave that day(3rd day) . This continues till day 100.

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XanderKage

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#56 XanderKage
Member since 2006 • 8956 Posts

^I hate reurtion problems...

Anyways, here's my row:

1, 11, 21, 1211, 111221, ________

Hint: it's easier then you're making of it.

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dave123321

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#57 dave123321
Member since 2003 • 35554 Posts

^I hate reurtion problems...

Anyways, here's my row:

1, 11, 21, 1211, 111221, ________

Hint: it's easier then you're making of it.

XanderKage

[spoiler] 312211 [/spoiler]

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XanderKage

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#58 XanderKage
Member since 2006 • 8956 Posts

[QUOTE="XanderKage"]

^I hate reurtion problems...

Anyways, here's my row:

1, 11, 21, 1211, 111221, ________

Hint: it's easier then you're making of it.

dave123321

[spoiler] 312211 [/spoiler]

-_-' You knew it before, admit it..

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dave123321

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#59 dave123321
Member since 2003 • 35554 Posts

-_-' You knew it before, admit it..

XanderKage

I do admit it.

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nintendo-4life

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#60 nintendo-4life
Member since 2004 • 18281 Posts

Another one 1,3,5,20,160,4000,______,2995200000

dave123321

i give -_-

HOLE UP I THINK I GOT IT!!! The answer is 720000

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nintendo-4life

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#61 nintendo-4life
Member since 2004 • 18281 Posts
more please! (BTW the riddle on top of the page requires a pen and paper.. please bring stuff that doesn't require that :P)
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dave123321

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#62 dave123321
Member since 2003 • 35554 Posts

An easy one : A slug is at the bottom of a well and decides to make it's way to the top. He climbs 3 feet each day , but slips down two feet during the night when sleeping. The well is 20 feet deep . How long does it take to get to the top?

What is unique about the following number? 854,917,632

A greek was born on the 260th day of 20 B.C and died on the 260th day of 60 A.D . How many years did he live ?

1,81,2025,3025,9801,88209,_______,998001,4941729
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nintendo-4life

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#63 nintendo-4life
Member since 2004 • 18281 Posts

An easy one : A slug is at the bottom of a well and decides to make it's way to the top. He climbs 3 feet each day , but slips down two feet during the night when sleeping. The well is 20 feet deep . How long does it take to get to the top?

What is unique about the following number? 854,917,632

A greek was born on the 260th day of 20 B.C and died on the 260th day of 60 A.D . How many years did he live ?

1,81,2025,3025,9801,88209,_______,998001,4941729 dave123321

I just woke up so...

1) 18 jumps till he gets out

2) all the numbers are present?

3) I don't now how to count B.C but i'm going to say 79? :lol: (which i know is wrong) as for the last one I need sometime to wake up and get back on.

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dave123321

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#64 dave123321
Member since 2003 • 35554 Posts
You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ?
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nintendo-4life

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#65 nintendo-4life
Member since 2004 • 18281 Posts
[QUOTE="dave123321"]You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ?

the second idea I had about number 2 was that it was even odd even- odd odd odd- even odd even but i'm still not sure about that. The third riddle is quite difficult, i spent a complete hour trying to solve it but to no avail. As for your new riddles. I need to work on one. but two... As far as I know cigarette ends can't be smoked :lol:
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dave123321

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#66 dave123321
Member since 2003 • 35554 Posts
While there is some symmetry for number two , the answer has to do with why this particular order is unique from any other other order of these particular numbers. (hint: do not think math) . As for the cigarette one , lets pretend that he has some device that allows him to make cigarette out of the ends.
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nintendo-4life

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#67 nintendo-4life
Member since 2004 • 18281 Posts
While there is some symmetry for number two , the answer has to do with why this particular order is unique from any other other order of these particular numbers. (hint: do not think math) . As for the cigarette one , lets pretend that he has some device that allows him to make cigarette out of the ends.dave123321
arghh there are 4 riddles right now >_
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nintendo-4life

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#69 nintendo-4life
Member since 2004 • 18281 Posts
[QUOTE="dave123321"]You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ?

hm.. I know the first riddle here means day,hour,minute,second... but I don't know what comes after that.. maybe split second? if so then SS. As for the second riddle. I'm sure this is wrong but i'm going to say 144.
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quijeros

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#70 quijeros
Member since 2008 • 1728 Posts

You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ? dave123321

For the second one, 157?

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dave123321

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#71 dave123321
Member since 2003 • 35554 Posts
[QUOTE="nintendo-4life"][QUOTE="dave123321"]You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ?

hm.. I know the first riddle here means day,hour,minute,second... but I don't know what comes after that.. maybe split second? if so then SS. As for the second riddle. I'm sure this is wrong but i'm going to say 144.

For the first one , it's just an interesting coincidence that it follows the pattern you described. The answer is a single letter. You are incorrect on the 2nd one.
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dave123321

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#72 dave123321
Member since 2003 • 35554 Posts
[QUOTE="quijeros"]

[QUOTE="dave123321"]You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ?

For the second one, 157?

That is correct.
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quijeros

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#73 quijeros
Member since 2008 • 1728 Posts

[QUOTE="quijeros"]

[QUOTE="dave123321"]You got 1 and 3 correct. 2 has to do with their order. Two more :

D,H,M,S,____

A man has collected 1728 cigarette ends , how many cigarettes could he make and smoke in total if 12 cigarette ends make one cigarette ? dave123321

For the second one, 157?

That is correct.

Yay, I feel smart!

For the first one, I think it's Z.

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dave123321

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#74 dave123321
Member since 2003 • 35554 Posts
[QUOTE="quijeros"]

[QUOTE="dave123321"][QUOTE="quijeros"]

For the second one, 157?

That is correct.

Yay, I feel smart!

For the first one, I think it's Z.

Right again.
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nintendo-4life

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#75 nintendo-4life
Member since 2004 • 18281 Posts
[QUOTE="quijeros"]

[QUOTE="dave123321"] That is correct. dave123321

Yay, I feel smart!

For the first one, I think it's Z.

Right again.

can you please explain both?
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dave123321

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#76 dave123321
Member since 2003 • 35554 Posts
There are 3 letters between D and H . 4 Between H and M . 5 between M and S . Following the pattern you get Z(6 letters between ) . For the cigarette one the 144 cigarettes will have 144 new ends. Those will make 12 new cigarettes. Then you get one last one. 144+12+1 = 157.
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nintendo-4life

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#77 nintendo-4life
Member since 2004 • 18281 Posts
Riddle 2) The numbers are listed in alphabetical form... I'm right right? :D the third riddle was too hard really.. i cheated TBH, but there was absolutely no way I could have known that without background knowledge.
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dave123321

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#78 dave123321
Member since 2003 • 35554 Posts
Riddle 2) The numbers are listed in alphabetical form... I'm right right? :D the third riddle was too hard really.. i cheated TBH, but there was absolutely no way I could have known that without background knowledge.nintendo-4life
That is correct . The other one was pretty hard.